# Line slope calculator 2x+y=3

**Straight line given by points A[0; 3] and B[1; 1]**

## Calculation:

**Slope-intercept form of line:**y = -2x+3

**Canonical form of the line equation:**2x+y-3 = 0

**Parametric form of the line equation:**

x = t

y = -2t+3 ; t ∈ R

**Slope:**m = -2

**Slope angle of line: φ =**-63°26'6″ = -1.1071 rad

**X intercept:**x

_{0}= 1.5

**Y intercept:**y

_{0}= q = 3

**Distance line from the origin:**d

_{0}= 1.3416

**The length of the segment AB: |AB| =**2.2361

**Vector: AB =**(1; -2)

**Normal vector: n =**(2; 1)

**Midpoint of the segment AB: M =**[0.5; 2]

**Perpendicular Bisector equation:**x-2y+3.5 = 0

**Vector OA = (0; 3) ; |OA| = 3**

**Vector OB = (1; 1) ; |OB| = 1.4142**

**Scalar product OA .OB = 3**

**Angle ∠ AOB = 45° = 0.7854 rad**